Daysapart.sh

From WikiPaul - Paul Swanson's wiki

I made a little bash script to tell me the difference between two days in Linux. It takes the one or two dates, converts them into seconds, subtracts them, divides by the number of seconds in a day, then prints it out.

#!/bin/bash

if [ $# -ne 1 ] && [ $# -ne 2 ]
then
  echo "Usage: $0 date1 [date2]"
  echo "    Standard date format \(mm/dd/yy\)"
  echo "    Omitting second date defaults to present date"
  echo "    You may omit years"                            
  exit
fi

DIFF=$(( (`date -d "$2" +%s` - `date -d "$1" +%s`) / 86400 ))

echo "$DIFF days apart"